X^2+30x-5400=0

Solution for X^2+30x-5400=0 equation:

X^2+30X-5400=0

a = 1; b = 30; c = -5400;
Δ = b2-4ac
Δ = 302-4·1·(-5400)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-150}{2*1}=\frac{-180}{2}
=-90
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+150}{2*1}=\frac{120}{2}
=60
$